f=kx,1N能拉长弹簧1cm
所以1=0.01k,∴k=100,
所以w=∫00.06100xdx=50x2|00.06=0.18(J)
故答案为0.18.
如果1N能拉长弹簧1cm,为了将弹簧拉长6cm,需做功_J.
如果1N能拉长弹簧1cm,为了将弹簧拉长6cm,需做功______J.
物理人气:674 ℃时间:2019-08-21 17:03:05
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