已知a²+4a+1=0,且（a四次方+ma²+1）÷（2a³+ma²+2a）=3,求m的值

a^2+4a+1=0a^2=-4a-1 a^3=a^2*a=-4a^2-a=-4(-4a-1)-a=16a+4-a=15a+4 a^4=(a^2)^2=16a^2+8a+1=16(-4a-1)+8a+1=-56a-15 (a^4+ma^2+1)/(2a^3+ma^2+2a)=3 a^4+ma^2+1=6a^3+3ma^2+6a 2ma^2=-6a^3-6a+a^4+1 把a^2,a^3,a^4...