首先,设个小学方程,设电阻为X
因为:I=U/R
得:(2+2)÷X-2÷x=0.1
=4/x-2/x=0.1
=2/x=0.1
x=2/0.1
=20
至于功率,
因为:P=UI,U增加2(电流I增加0.1是理所当然),
用快捷算法吧,P=uu/r
得:4×4÷20-2×2÷20=0.6W
定值电阻两端的电压为2伏增加到4伏,电流增加0.1安,电阻R为多少,功率增加了多少
定值电阻两端的电压为2伏增加到4伏,电流增加0.1安,电阻R为多少,功率增加了多少
数学人气:207 ℃时间:2019-08-20 10:14:49
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