1+sinx=2y+ycosx sinx-ycosx=2y-1 ( 根号下(y^2+1))*sin(x+a)=2y-1
sin(x+a)=(2y-1)/ 根号下(y^2+1) 此式小于等于1
求得 0=
函数y=(1+sinx)/(2+cosx)的值域为多少?
函数y=(1+sinx)/(2+cosx)的值域为多少?
数学人气：562 ℃时间：2020-01-30 06:03:58
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