已知p-2p-5=0,5q+2q-1=0,其中p,q是实数,求p+1／q的值

p-2p-5=0,5q+2q-1=0 p^2-2p+1=6,q^2+2q/5+1/25=6/25 (p-1)^2=6,(q+1/5)^2=6/25 p=1+/-6^0.5,q=-1/5+/-6^0.5/5 p^2+1=7+/-2x6^0.5,q^2=7/25-/+2x6^0.5/25 (p^2+1)/q^2=25