f(x)=y=(x²-2x+2)/x=x+2/x-2
设定义域上x1,x2,且0
已知0小于x小于等于1/4,求函数Y=x^2-2x+2/x的值域
已知0小于x小于等于1/4,求函数Y=x^2-2x+2/x的值域
数学人气:296 ℃时间:2019-09-27 05:43:10
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