log2为底(x+1)
log2为底(x+1)
数学人气:693 ℃时间:2019-10-09 11:41:23
优质解答
log2[x+1]≤log4[3x+1]定义:x+1>0 x>-13x+1>0 x>-1/3log2[x+1]≤(1/2)log2[3x+1]2log2[x+1]≤log2[3x+1]log2[x+1]²≤log2[3x+1](x+1)²≤3x+1x²+2x+1≤3x+1x²-x≤0x(x-1)≤0得0≤x≤1...
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