设等比数列｛an｝的前n项和是Sn,若S6/S3=3则S9/S6等于几

S6=a1(q^6-1)/(q-1)S3=a1(q^3-1)/(q-1)S6/S3=(q^6-1)/(q^3-1)=3(q^3+1)(q^3-1)/(q^3-1)=3q^3+1=3q^3=2S9=a1(q^9-1)/(q-1)所以S9/S6=(q^9-1)/(q^6-1)=(q^3-1)(q^6+q^3+1)/(q^3+1)(q^3-1)=(q^6+q^3+1)/(q^3+1)=(4+2+1)...