函数f(x)=sinx-cos(x+pai/6)的值域为什么是[-根号3,根号3]

原题：函数f(x)=sinx-cos(x+π/6)的值域为什么是[-√3,√3]?f(x)=sinx-cos(x+π/6)=sinx-sin(x+2π/3)=sin[(x+π/3)-π/3]-sin[(x+π/3)+π/3]=-2cos(x+π/3)sin(π/3)=-√3cos(x+π/3)其值域是[-√3,√3].希望对你...