lim(n→∞)(3∧n-2∧n)/((3∧n+1)-(2∧n+1))
分子分母同除以3^n,得
lim(n→∞)(1-(2/3)∧n)/((3-((2/3)∧n×2)
=(1-0)/(3-0)
=1/3
lim(n→∞)(3∧n-2∧n)/((3∧n+1)-(2∧n+1))
lim(n→∞)(3∧n-2∧n)/((3∧n+1)-(2∧n+1))
数学人气:775 ℃时间:2020-03-26 08:33:22
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