(x-1)ⁿ﹢¹-x(x-1)ⁿ=1
(x-1)ⁿ [(x-1) -x] = 1
(x-1)ⁿ = - 1
n 为偶数时,无实数根
n 为奇数时,x-1 = -1,x = 0
求方程(x-1)ⁿ﹢¹-x(x-1)ⁿ=1的实数根(n为自然数)
求方程(x-1)ⁿ﹢¹-x(x-1)ⁿ=1的实数根(n为自然数)
数学人气:624 ℃时间:2019-10-06 22:17:16
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