已知A,B两点的坐标分别为（3,-1）,（-4,-2）,P是直线AB上的点,若向量AP=2*向量PB,求P的坐标

P = A + t(B-A) AP = P - A = t(B-A),PB = B - P = B-A - t(B-A) = (1-t)(B-A),AP = t(B-A) = 2*PB = 2(1-t)(B-A),0=(2-2t-t)(B-A)=(2-3t)(B-A)B-A=(-7,-1),B-A不为0向量.所以,0=2-3t,t = 2/3.P = A + t(B-A)=(3,-1)...