解∶x﹙x+y﹚﹙x-y﹚-x﹙x+y﹚²
=x﹙x+y﹚﹙x-y﹚-x﹙x+y﹚﹙x+y﹚
=x﹙x+y﹚[﹙x-y﹚-﹙x+y﹚]
=x﹙x+y﹚﹙x-y-x-y﹚
=x﹙x+y﹚﹙﹣2y﹚
=﹙﹣2xy﹚﹙x+y﹚
=﹙﹣2﹚× ½× 1
=﹣1
欢迎追问,若满意望采纳O(∩_∩)O
利用因式分解求x(x+y)(x-y)-x(x+y)^2的值,其中x+y=1,xy=1/2.完整一点
利用因式分解求x(x+y)(x-y)-x(x+y)^2的值,其中x+y=1,xy=1/2.完整一点
数学人气:371 ℃时间:2020-02-18 19:13:39
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