如图,ABCD为一矩形,E,F分别是BC,CD上的点,且S△ABE=3,S△CEF=2,S△ADF=2,则S△AEF=( )

因为S△ABE=S△ADF=1/3SABCD所以E和F分别在BC和DC的2/3处,靠近C点.且四边形AECF面积为1/3(SABCD)所以,S△CEF = 1/2 * 1/3(DC) * 1/3(BC) =1/18(SABCD)所以,S△AEF = SAECF - S△CEF = 5/18(SABCD)所以,S△AEF/S△CEF...