设m是实数,记M={m|m>1},f(x)=log3(x^2-4mx+4m^2+m+1/(m-1)),

设g(x)=x^2-4mx+4m^2+m+1/(m-1)为开口向上的抛物线,对称轴x=2m所以g(x)最小=g(2m)=m+1/(m-1)因m>1 m-1>0所以g(2m)=1+(m-1)+1/(m-1)≥1+2√[(m-1)*1/(m-1)]=3所以g(x)≥3所以f(x)=log3 g(x)≥log3 3=1故对每个m∈M,函...