如果一弓形的弧所对的圆心角是π/3,弓形的弦长是2cm,则弓形的面积是?

设圆心为O,弓形的弦为AB,则AB＝2,∠AOB＝π/3过O作OP⊥AB于P,则AP＝AB/2＝2cm/2＝1cm∠AOP＝∠AOB/2＝π/3/2＝π/6所以,半径R＝AP/sinπ/6＝1cm/(1/2)=2cm弧长为：L＝π/3*R＝π/3*2＝2π/3扇形面积：S1＝1/2*L*R＝1...