f(x)满足:
f(-2+x)=f(-2-x),
用x-2代替x,
f(-4+x)=f(-x)=-f(x)(奇偶性)
再用x+4代替x,
f(x)=-f(x+4),
f(x+8)=f[(x+4)+4]=-f(x+4)=f(x),
f(x)周期为8
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