2f（x-1）+f（3-x）＝x2 求f（x）表达式

2f(x-1)+f(3-x)=x^2令x-1=t2f(t)+f(2-t)=(1+t)^2 (1)令3-x=t2f(2-t)+f(t)=（3-t）^2 (2)(1)*2-(2)得3f(t)=2(1+t)^2-(3-t)^23f(t)=2+4t+2t^2-9+6t-t^23f(t)=t^2+10t-7f(t)=1/3t^2+10/3t-7/3则有f(x)=1/3x^2+10/3x-7/3...