a³-b³
=1/8+1
=9/8
(a-b)(a²+ab+b²)
=(1/2+1)×(1/4-1/2+1)
=3/2×3/4
=9/8
已知a=1/2,b=-1,分别求代数式①a³;-b³ ②(a-b)(a²;+ab+b;)的值
已知a=1/2,b=-1,分别求代数式①a³;-b³ ②(a-b)(a²;+ab+b;)的值
数学人气：832 ℃时间：2020-03-23 12:20:35
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