已知等比数列{An}的公比为q,前n项和为Sn,且S3,S9,S6成等差数列

因为S3.S9.S6成等差数列 2S9=S3+S6 2a1(1-q^8)/(1-q)=a1(1-q^2)/(1-q)+a1(1-q^5)/(1-q) 2(1-q^8)=2-q^2-q^5 2q^8=q^2+q^5 2q^7=q+q^4 2a1q^7=a1q+a1q^4 2a8=a2+a5 所以a2.a8.a5成等差数列