已知向量a=(cosa,sina),b=(cosβ,sinβ),0
已知向量a=(cosa,sina),b=(cosβ,sinβ),0<β
数学人气：961 ℃时间：2019-10-04 06:48:27
优质解答
(1)|a-b|^2=(cosa-cosb)^2+(sina-sinb)^2=2所以(cosa)^2+(cosb)^2-2cosacosb+(sina)^2+(sinb)^2-2sinasinb=2所以sinasinb+cosacosb=0因为a*b=cosacosb+sinasinb=0,所以a垂直b(2)a+b=(cosa+cosb,sina+sinb)=c=(0,1)所...
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