化简cos(2π/3-x)+cos(2π/3+x)+cosx

cos(2π/3-x)+cos(2π/3+x)+cosx
= cos(2π/3)cosx+sin(2π/3)sinx+cos(2π/3)cosx-sin(2π/3)sinx+cosx
= -cos(π/3)cosx+sin(π/3)sinx-cos(π/3)cosx-sin(π/3)sinx+cosx
= -cos(π/3)cosx-cos(π/3)cosx+cosx
= -(1/2)cosx-(1/2)cosx+cosx
= 0