|ab-2|+（1-b）²=0
所以ab-2=0
1-b=0
所以b=1
a=2/b=2
所以原式=1/1×2+1/2×3+……+1/2011×2012
=1-1/2+1/2-1/3+……+1/2011-1/2012
=1-1/2012
=2011/2012
如果有理数a,b满足|ab-2|+（1-b）²=0；
如果有理数a,b满足|ab-2|+（1-b）²=0；
试求ab分之1+（a+1)(b+1)分之一+…+（a+2010)(b+2010)分之一+?
试求ab分之1+（a+1)(b+1)分之一+…+（a+2010)(b+2010)分之一+?
数学人气：451 ℃时间：2020-04-10 18:11:41
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