即a+b=0
cd=1
x=±2
所以x²=4
元素=4-)0+1)x+0^2012+(-1)^2012
=4-x+0+1
=5x
=5+2=7或5-2=3
已知a、b互为相反数,a、b互为倒数,x的绝对值等于2,试求:x^2-(a+b+cd)x+(a+b)^2012+(—cd)^2012的值
已知a、b互为相反数,a、b互为倒数,x的绝对值等于2,试求:x^2-(a+b+cd)x+(a+b)^2012+(—cd)^2012的值
数学人气:502 ℃时间:2019-11-07 20:08:53
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