掷骰子6次,求正好有3次是5,1次是1的概率,顺序无所谓.

6次正好有3次是5,1次是1,其余2次为其它C(6,3)*(1/6)^3*C(3,1)*(1/6)*(2/3)²=60*2²/(6⁴×3²)=10*2²/(6³×3²)=400/(216*9=100/(54*9)=50/243【中学生数理化】团队为您答题,请点击...ʽ���ǶԵģ��������ʮ��֮һ= =��ǰ���������©C(6,3)*(1/6)^3*C(3,1)*(1/6)*(2/3)²=60*2²/(6⁴��3²)=10*2²/(6³��3²)=40/(216*9=10/(54*9)=5/243