已知函数f(x)=Acos^2(wx+φ )+1(A>0,w>0,0

(1)因为f(x)的最大值为3,所以A=2.
f(x)=2cos^2(wx+φ)+1=cos(2wx+2φ)+2.
f(x)的图像的相邻两对称轴间的距离为2,则最小正周期为4.
T=2π/2w=4,则w=π/4.
f(x)=cos(xπ/2+2φ)+2.
f(0)=cos2φ+2=2,则cos2φ=0.
0