1:
BC=1/4AC=1/4(AB+BC),BC=1/3AB=2
DA=1/3AB=2
CD=DA+AB+BC=2+2+6=10
2:
DM=DA+AM=3+2=5
MC=MB+BC=3+2=5
DM=MC
所以M是CD的中点
已知线段AB=30,延长AB至C使BC=1/4AC,点D线段BA延长线上的一点,DA=1/3AB,M是AB 中
已知线段AB=30,延长AB至C使BC=1/4AC,点D线段BA延长线上的一点,DA=1/3AB,M是AB 中
点,若AB=6CM,(1)求CD长(2)点M是那条线段的中点
点,若AB=6CM,(1)求CD长(2)点M是那条线段的中点
数学人气:644 ℃时间:2020-01-29 21:23:28
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