原式=(-2002/2003)X(-2001/2002)X(-2000/2001)...(-1000/1001)X(-999/1000)
=999/2003
求(1/2003-1)X(1/2002-1)X(1/2001-1)X(1/2000-1)X1/1999-1)...(1/1001-1)X(1/1000
求(1/2003-1)X(1/2002-1)X(1/2001-1)X(1/2000-1)X1/1999-1)...(1/1001-1)X(1/1000
数学人气:746 ℃时间:2019-10-11 20:30:42
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