1、∵OA=OC,OB=OD,∠AOB=∠COD
∴△AOB≌△COD
∴AB=CD,∠ABO=∠CDO
∴AB∥CD
∴ABCD是平行四边形
∴AD∥BC
2、∵OA=OC,OB=OD
∴ABCD是平行四边形
∴AB∥CD,AD∥CB初二的题∵OA=OC,OB=OD,∠AOB=∠COD∴△AOB≌△COD∴∠ABO=∠CDO∴AB∥CD(内错角相等)∵OA=OC,OB=OD,∠AOD=∠BOC∴△AOD≌△BOC∴∠CBO=∠ADO∴AD∥BC
已知,如图,AC,BD交于O点,且OA=OC,OB=OD.求证:AB平行CD,AD平行BC.
已知,如图,AC,BD交于O点,且OA=OC,OB=OD.求证:AB平行CD,AD平行BC.
数学人气:484 ℃时间:2019-12-02 02:57:37
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