用0.1mol/L的HCL 25ml中和0.1mol/L的NaOH 25ml,当HCL过量一滴(体积约为0.05ml)时,求其PH?当NaOH过量一滴时,求PH=?

当HCL过量一滴(体积约为0.05ml)时,pH?
这时总体积=50.05 mL
溶液中过量HCl浓度=0.1 mol/L x 0.05 mL/50.05 mL= 0.0001 mol/L
pH= 4
当NaOH过量一滴时,pH=?
同理,pOH = 4 ==> pH=10