[sin(7π/2+a)*cos(a-π)*sin^2 (a+2π)]/[cos(3π/2+a)*tan(π+a)*cos^3(-a-π)]
=[-cosa*(-cosa)*sin^2a]/[sina*tana*(-cos^3a)]
=cos^2asin^2a/sin^2a(-cos^2a)
=-1
高一三角函数 化简求值
高一三角函数 化简求值
[sin(7π/2+a)*cos(a-π)*sin^2 (a+2π)]/[cos(3/2+π)*tan(π+a)*cos^3(-a-π)]
[sin(7π/2+a)*cos(a-π)*sin^2 (a+2π)]/[cos(3/2+π)*tan(π+a)*cos^3(-a-π)]
数学人气：450 ℃时间：2020-06-22 19:09:01
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