原式=a(3a-6-a-2)/(a+2)(a-2)×[-(a+2)(a-2)/2a]
=-2a(a-4)/(a+2)(a-2)×(a+2)(a-2)/2a
=-(a-4)
=4-a
先化简((3a/a+2)-(a/a-2))÷(2a/4-a²)
先化简((3a/a+2)-(a/a-2))÷(2a/4-a²)
数学人气:209 ℃时间:2019-10-11 10:46:26
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