已知实数a满足a^2+2a-1=0,求a+1分之1-a^2-1分之a+3×a^2+4a+3分之a^2-2a+1的值

原式=[1/(a+1)]-[(a+3)/(a²-1)]×[(a²-2a+1)/(a²+4a+3)]=[1/(a+1)]-{(a+3)/[(a+1)(a-1)]}×{(a-1)²/[(a+1)(a+3)]}=[1/(a+1)]-[(a-1)/(a+1)²]=[(a+1)/(a+1)²]-[(a-1)/(a+1)²]=[(a...