已知【8x³y³-（-xy²）²】/A=-x²y²+（1/8）xy³求A+4x

【8x³y³-（-xy²）²】/A=-x²y²+（1/8）xy³即有[8x^3y^3-x^2y^4]/A=-x^2y^2+1/8xy^3A=[8x^3y^3-x^2y^4]/(-x^2y^2+1/8xy^3)=xy^2[8x^2y-xy^2]/[xy^2(1/8y-x)]=(8x^2y-xy^2)/(1/8y-x...对不起，答案应该为-2y.望能得到您的指导。如果是A/4x=-8xy/4x=-2y