已知复数Z1=cosα-i,Z2=sinα+i,求ㄧZ1*Z2ㄧ的最大值,最小值

Z1*Z2=(cosα-i)*(sinα+i)=(cosαsinα+1)+i(cosα-sinα).|Z1*Z2|^2=(cosαsinα+1)^2+(cosα-sinα)^2=1+(cosαsinα)^2+(cosα)^2+(sinα)^2=2+(sin2α)^2/4.(sin2α)^2的最大值,最小值分别是1,0,所以ㄧZ1*Z2ㄧ...