1.已知2.00%的硫酸铜溶液的密度为1.02g/ml,欲配置500ml这种溶液,需要胆矾多少克?所得溶液的物质的量浓度是多少?

1.
m(cuso4溶液)=1.02*500=510g;
m(cuso4)=510*2.00%=10.2g;
Cuso4 Cuso4.5H2O
160 250
10.2g x
x=250/160*10.2g=15.9375g
n(Cuso4)=10.2/160 mol=0.06375mol;
c(Cuso4)=n/v=0.06375/0.5 mol/l=0.1275mol
2.
n=v/22.4=25 mol;
m(氨气）=25*17g=425g;
m(水）+m(氨气）=1000g+425g=1425g;
v=m/p=1425/0.9 ml=1583.3ml=1.60l;
c=n/v=25/1.60 mol/l=15,62mol/l;
3.
CaCl2.nH2O CacCL2
111+18n 111
26.28g 13.32g
111+18n/26.28=111/13.32
解得 n=6;
43.80g的CaCL2.6H2O的物质的量为0.2摩尔
C（cacl2)=n/v=0.2/0.5 mol/l=0.4mol/l