| sinx |
| sinx+cosx |
| 1 |
| 2 |
∴y'=
| cosx(sinx+cosx)−(cosx−sinx)sinx |
| (sinx+cosx)2 |
=
| 1 |
| (sinx+cosx)2 |
y'|x=
| π |
| 4 |
| 1 |
| (sinx+cosx)2 |
| π |
| 4 |
| 1 |
| 2 |
故选B．
曲线y＝sinxsinx+cosx−12在点M（π4，0）处的切线的斜率为（ ） A.−12 B.12 C.−22 D.22
曲线y＝
−
在点M（
，0）处的切线的斜率为（ ）
A. −
B.
C. −
D.
| sinx |
| sinx+cosx |
| 1 |
| 2 |
| π |
| 4 |
A. −
| 1 |
| 2 |
B.
| 1 |
| 2 |
C. −
| ||
| 2 |
D.
| ||
| 2 |
数学人气：419 ℃时间：2019-12-16 01:38:43
优质解答
∵y＝
−
∴y'=
=
y'|x=
=
|x=
=
故选B．
∴y'=
=
y'|x=
故选B．
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