根据h=v0t-1/2gt²
h6=v0*6-1/2g*6²=6v0-180
h5=v0*5-1/2g*5²=5v0-125
h6-h5=-3
(6v0-180)-(5v0-125)=-3
v0 = 52m/s
将一物体竖直上抛,物体在第6S内落下的距离为3m,求抛出的初速度
将一物体竖直上抛,物体在第6S内落下的距离为3m,求抛出的初速度
物理人气:690 ℃时间:2019-11-22 23:25:40
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