已知正项数列{an},{bn}满足:对任意正整数n,都有an,bn,a(n+1)成等差数列,bn,a(n+1),b(n+1)成等比数列
已知正项数列{an},{bn}满足:对任意正整数n,都有an,bn,a(n+1)成等差数列,bn,a(n+1),b(n+1)成等比数列
且a1=10,a2=15,(1)求数列{√bn}是等差数列,(2)求{an}{bn}的通项公式(3)设Sn=1/a1+1/a2+.+1/an,如果对任意正整数n,不等式2aSn<2-bn/an,求实数a的取值范围
且a1=10,a2=15,(1)求数列{√bn}是等差数列,(2)求{an}{bn}的通项公式(3)设Sn=1/a1+1/a2+.+1/an,如果对任意正整数n,不等式2aSn<2-bn/an,求实数a的取值范围
数学人气:523 ℃时间:2020-05-25 21:52:30
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1、an,bn,a(n+1),所以,2bn=an+a(n+1)推出,2(bn+1)=a(n+1)+a(n+2)bn,a(n+1),b(n+1),所以,a(n+1)^2=bn*b(n+1),推出,a(n+1)=根号下【bn*b(n+1)】,a(n+2)=根号下【b(n+1)*b(n+2)】,带入2(bn+1)=a(n+1)+a(n+2)并化简,得到...
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