(x+2/x-2+4/x平方-4x+4)÷x/x-2*x-2/x
=[(x+2)/(x-2)+4/(x-2)²]÷x/(x-2)*(x-2)/x
=(x²-4+4)/(x-2)²*(x-2)/x*(x-2)/x
=x²/(x-2)²*(x-2)²/x²
=1
分式计算 (x+2/x-2+4/x平方-4x+4)÷x/x-2*x-2/x
分式计算 (x+2/x-2+4/x平方-4x+4)÷x/x-2*x-2/x
数学人气:579 ℃时间:2020-03-27 23:29:30
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