不妨设取用Фв=0.95的酒精溶液体积为V1,取用Фв=0.35的酒精溶液体积为V2.
由于配置前后,酒精总量不变,则有:0.95*V1+0.35*V2=0.75*(V1+V2),可以算出V1:V2=2:1.用因为V1+V2=300ml.故算出V1=200ml,V2=100ml
如如何用Фв=0.95和Фв=0.35的酒精溶液配制Фв=0.75的消毒酒精300ml?
如如何用Фв=0.95和Фв=0.35的酒精溶液配制Фв=0.75的消毒酒精300ml?
数学人气:251 ℃时间:2019-10-11 00:19:29
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