∵A、B两点关于原点对称,可设A(x,y),则B(-x,-y),x>0.
y=x^2+4x-2 ①
-y=x^2-4x-2 ②
①+②得:2x^2-4=0,∴x=√2,y=4√2;
故A(√2,4√2),B(-√2,-4√2).
若抛物线y=x2+4x-2上有A、B两点,且原点位于线段A、B中点处,则这两点坐标为?
若抛物线y=x2+4x-2上有A、B两点,且原点位于线段A、B中点处,则这两点坐标为?
数学人气:879 ℃时间:2020-04-02 14:35:15
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