设U=R,集合A={x|x2+3x+2=0},B={x|x2+(m+1)x+m=0};若（A在U中补集）交B=空集,求m的值

x²+3x+2=0(x+1)(x+2)=0x=-1或x=-2A={-1,-2}x²+(m+1)x+m=0(x+m)(x+1)=0x+m=0或x+1=0x=-m或x=-1(CuA)∩B=空集CuA={x|x≠-1且x≠-2}所以B={-1}或B={-1,-2}所以-m=-1或-m=-2求得,m=1或m=2