∵a1+a4+a10+a16+a19=5a10=150,
∴a10=30,
则a20-a26+a16=(a1+19d)-(a1+25d)+(a1+15d)
=a1+9d=a10=30.
故答案为:30
等差数列{an}中,a1+a4+a10+a16+a19=150,则a20-a26+a16的值是_.
等差数列{an}中,a1+a4+a10+a16+a19=150,则a20-a26+a16的值是______.
数学人气:338 ℃时间:2020-10-02 03:05:11
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