设函数z=z(x,y)由方程x+2y-z=3e^(xy-xz)确定,则dz(0,0)=?

x+2y-z=3e^(xy-xz)两边对x求导,z看成是x的函数求偏导得,y看成常数,得1-əz/əx=3(y-z-xəz/əx)e^(xy-xz)=>əz/əx=[1-3(y-z)e^(xy-xz)]/[1-3xe^(xy-yz)]原方程中令x=y=0,得z=-3,即z(0,0)=-...