原式=(x²-4y²+4x²-8xy+4y²)÷6x
=(5x²-8xy)÷6x
=5x/6-4y/3
原式=6x²-13x+6-6x²+x+12x-12
=-6
求过程【(x+2y)(x-2y)+4(x-y)²】÷6x (2x-3)(3x-2)-x(6x-1)+12(x-1)
求过程【(x+2y)(x-2y)+4(x-y)²】÷6x (2x-3)(3x-2)-x(6x-1)+12(x-1)
数学人气:342 ℃时间:2019-11-07 13:59:16
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