角aoc=25
所以角aod=180-角aoc=155
因为ef 角aod
所以角aof=角aod/2=77.5
角cof=角aoc+角aof=102.5
已知直线AB与CD相交于点O,EF平分∠DOA,∠AOC=25°,求∠COF的度数.
已知直线AB与CD相交于点O,EF平分∠DOA,∠AOC=25°,求∠COF的度数.
RT、
RT、
数学人气:977 ℃时间:2019-12-14 17:52:20
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