①当a=0时,1-x<0
x>0继续②当a≠0时,(a+1)∧2-4a=(a-1)∧2≥0 所以有 i)当a=1时,x∈R那个①是x>1,写错了。继续ii )当a>1时,则x<1或x>a完了?又写错了,应该是 ii )当a>1时,则a<x<1还有呢。iii )当0<a<1时, a<x<1a=1解集为空集 a>1,1/a<x<1iiii)当a<0时, x<a或x>10<a<1,1<x<1/a我看错符号了,错了一大片,不过思路就是这样。你的思路给了我灵感
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