计算公式：m=ρV=πρ(R^2-r^2)L
其中无缝钢管密度ρ=7.85*10^3 kg/m^3,故质量=3.14*7.85*10^3*(0.025^2-0.021^2)*1=4.535kg
这是理论值,实际上密度达不到7.85*10^3 kg/m^3,即实际重量比这个轻,一般是3.749kg.
内径42毫米壁厚4毫米的无缝钢管1米有多重?
内径42毫米壁厚4毫米的无缝钢管1米有多重?
求计算公式和结果
求计算公式和结果
物理人气：969 ℃时间：2020-03-19 11:02:27
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