如果多项式X^4-AX^3+5X^2+BX+X^3-1+3X中不含X^3和X项,即X^3和X项前的系数为0
X^4-AX^3+5X^2+BX+X^3-1+3X
=X^4-(A-1)X^3+5X^2+(B+3)X-1
因此A-1=0,B+3=0
所以A=1,B=-3
A+B=1-3=-2
如果多项式X^4-AX^3+5X^2+BX+X^3-1+3X中不含X^3和X项,则A+B=?
如果多项式X^4-AX^3+5X^2+BX+X^3-1+3X中不含X^3和X项,则A+B=?
数学人气:401 ℃时间:2019-08-19 08:12:56
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